Goal: To compute pn = P{n cells in system}, when n = 0, 1, 2, . . .
Global Balance Equations: For any given state n, we have

Here Pij = P{go to state j | in state i}, i.e. Pij is the probability of moving to state j given that the system is currently in state i.
When n = 0, we have

When n = 1, we have

Hence

When n = 2, we have

Hence

When n is arbitrary, we have

From this, we can solve for each pn in terms of p0.
For typical distributions for Ai, Ai goes to 0 quickly as i goes to infinity.
Problem with Input Queuing is Head of Line (HoL) Blocking.
Let
=
number of cells destined for output j, but not served at time
i.
=
number of cells served at time i-1.
Thus
= number of HoL slots "freed up" for use at time i.
So,
=
Now, let
=
number of cells destined for j which move to the HoL at time i.
We can think of these as the "arrivals" to the HoL at time i.
Since cell destinations are independent from slot to slot, each HoL cell has probability 1/N of being destined for output j, so
for 
We also can show that for large N
with 
to a
binomial distribution.)
For more details, see "Input Versus Output Queueing on a Space-Division Packet Switch," by M.J. Karol, M.G. Hluchyj, and S.P. Morgan, IEEE Transactions on Communications, Vol. 35, No. 12, Dec. 1987, pp. 1347-1356.